How do you multiply $(3 x^{2} + 2 y) (7 x^{2} + 3 y)$ $(3x^2 + 2y)(7x^2 + 3y)$ ?

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How do you multiply $(3 x^{2} + 2 y) (7 x^{2} + 3 y)$ $(3x^2 + 2y)(7x^2 + 3y)$ ?

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Answer 1 · 2016-07-26T21:21:21

$(3 x^{2} + 2 y) (7 x^{2} + 3 y)$ $(3x^2 + 2y) (7x^2 + 3y)$

$21 x^{4} + 9 x^{2} y + 14 x^{2} y + 6 y^{2}$ $21x^4 + 9x^2 y+ 14x^2y +6y^2$

$21 x^{4} + 23 x^{2} y + 6 y$ $21x^4 + 23x^2y+6y$

Explanation:

Step 1
I multiplied
$3 x^{2}$ $3x^2$ with $7 x^{2}$ $7x^2$
Step 2
I multiplied $3 x^{2}$ $3x^2$ with $3 y$ $3y$ .
So far we have $21 x^{4} + 9 x^{2} y$ $21x^4 + 9x^2y$
Step 3
I multiplied $2 y$ $2y$ with $7 x^{2}$ $7x^2$
Step 4
I multiplied $2 y$ $2y$ with $3 y$ $3y$ .
We have $14 x^{2} y + 6 y^{2}$ $14x^2y + 6y^2$
Step 5
In total, we have $21 x^{4} + 9 x^{2} y + 14 x^{2} y + 6 y^{2}$ $21x^4+9x^2y+14x^2y+6y^2$
Step 6
We combine like terms. You will see the only like terms are $9 x^{2} y + 14 x^{2} y$ $9x^2y+14x^2y$ Those are the only terms we combine.
Final Step
We combine everything
SO our answer is $21 x^{4} + 23 x^{2} y + 6 y^{2}$ $21x^4+23x^2y+6y^2$

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How do you multiply $(3 x^{2} + 2 y) (7 x^{2} + 3 y)$ $(3x^2 + 2y)(7x^2 + 3y)$ ?

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Explanation:

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How do you multiply (3x^2 + 2y)(7x^2 + 3y)(3x2+2y)(7x2+3y)(3x^2 + 2y)(7x^2 + 3y)?

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How do you multiply $(3 x^{2} + 2 y) (7 x^{2} + 3 y)$ $(3x^2 + 2y)(7x^2 + 3y)$ ?