Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you simplify #(3pi)/2 +pi/4#?

1 Answer

Jul 10, 2016

We can make use of the property

#a/b + c/d = ((a*d)+(b*c))/(b*d)#

Therefore, #(3pi)/(2) + (pi)/(4) = (12pi + 2pi)/(8) =(14pi)/(8)#

Since both #14# and #8# are divisible by #2#, we can simplify further and write

#(14pi)/(8) = (7pi)/(4)#

Related questions

See all questions in Addition of Rational Numbers

Impact of this question

4625 views around the world

You can reuse this answer
Creative Commons License