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How do you simplify #(3pi)/2 +pi/4#?

1 Answer

Jul 10, 2016

We can make use of the property

#a/b + c/d = ((a*d)+(b*c))/(b*d)#

Therefore, #(3pi)/(2) + (pi)/(4) = (12pi + 2pi)/(8) =(14pi)/(8)#

Since both #14# and #8# are divisible by #2#, we can simplify further and write

#(14pi)/(8) = (7pi)/(4)#

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