A projectile is shot from the ground at a velocity of #3 m/s# and at an angle of #(7pi)/12#. How long will it take for the projectile to land?

1 Answer
Cameron G.
Jul 7, 2016

#0.0196s#

Explanation:

The equation to find time of flight given angle and speed of launch is:
#t=(2v_osin(theta))/g#
where:
#t# is the time taken to hit the ground
#v_o# is the launch speed of the projectile (#3ms^-1)#
#theta# is the angle of launch (#(7pi)/12#)
#g# is the acceleration due to gravity (#9.81ms^-1#)

We then substitute these values into the equation

#t=(2(3ms^-1)sin((7pi)/12))/(9.81ms^-1`)#

#t=0.01955s = 0.0196s" (3 s.f.")#

For more projectile motion formulas look here.

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