How do you solve $abs[5-2x] = 41$ ?

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Answer 1 · 2016-07-01T11:02:38

$x \in {-18, 23}$ .

$abs{5-2x} = 41 \iff 5-2x = 41 or 5-2x = -41$ .

In the first case : $-2x = 36 \iff x = -18$ .

In the second case : $-2x = -46 \iff x = 23$ .

How do you solve abs[5-2x] = 41abs[5-2x] = 41?