How do you write the standard from of the equation of the circle given center (5,-3) and radius 7?

1 Answer
Jun 29, 2016

(x-5)^2+(y+3)^2=49

Explanation:

The standard form of the equation of a circle is

color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))
where (a ,b) are the coordinates of the centre and r, the radius.

Here centre = (5 ,-3) hence a = 5 , b = -3 and r = 7

Substitute these values into the standard equation.

(x-5)^2+(y-(-3))^2=7^2

rArr(x-5)^2+(y+3)^2=49" is the equation"