In a particular television tube, the beam current is 50.0 micro A. How long does it take for #4.75 * 10^14# electrons to strike the screen?

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Answer 1 · 2016-06-18T20:23:45

It takes #1.52"s"#.

The definition of Ampère is

#1"A"=1"C"/"s"#

we have #50\mu "A"=50*10^-6"C"/"s"#.

We have to know how many Coulombs of charge do we have in #4.75*10^14# electrons.

The charge of an electron is #1.6*10^(-19)"C"#, then our beam has

#4.75*10^14*1.6*10^(-19)"C"=7.6*10^-5"C"#.

The time to transport #7.6*10^-5"C"# in a current of #50\mu"A"# is then

#t=(7.6*10^-5"C")/(50*10^-6"C"/"s")=1.52"s"#.