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If #h(n) = -2n^3 + 1# and #g(n) = -n-3#, what is #h(-2) + g(-2)#?

1 Answer

Jun 5, 2016

16

Explanation:

let's substitute n by -2 in the first one
#h(-2)=-2(-2)^3+1#
#h(-2)=16+1=17#

let's substitute n by -2 n the second one
#g(-2)=-(-2)-3#
#g(-2)=-1#

then

#h(-2)+g(-2)=17-1=16#

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