How do you factor the expression 15x2−33x−5?

1 Answer
Maggie
Jun 1, 2016

This equation does not have simple factor-able terms

Explanation:

15⋅(−5)=75 we need factors of −75 which sum to −33.

(−15)⋅(5)=75 and 5−15=−10 No

(−3)⋅(25)=75 and 25−3=22 No

(−1)⋅(75)=75 and 75−1=74 No

(15)⋅(−5)=75 and −5+15=10 No

(3)⋅(−25)=75 and −25+3=−22 No

(1)⋅(−75)=75 and −75+1=−74 No

This expression is NOT simple factor-able.

We can check Quadratic equation
x1,x2=(−b2a)±√b2−4ac2a

x1,x2=(−−332⋅15)±√(−33)2−4⋅15⋅(−5)2⋅15

x1,x2=3330±√1089+6030

x1,x2=3330±√114930

x1,x2=2.22989675,−0.02989675

Clearly this equation does not have simple factor-able terms

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