How do you find the derivative of $\frac{4}{x + 3}$ $4 / (x+3)$ ?

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Answer 1 · 2016-05-31T00:51:20

$- \frac{4}{{(x + 3)}^{2}}$ $-4/(x+3)^2$

We would need to use the Derivative rules.
A. Constant Rule
B. Power Rule
C. Sum & Difference Rule
D. Quotent Rule
Apply the specific Rules

$\frac{d}{d x} (4) = 0$ $d/dx (4) = 0$

$\frac{d}{d x} (x + 3) = 1 + 0$ $d/dx (x+3) = 1+0$

Now to set up the Quotent Rule for the whole function:
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$\frac{(0) (x + 3) - (4) (1)}{{(x + 3)}^{2}}$ $((0) (x+3) - (4) (1))/(x+3)^2$

simplify and you get:

$- \frac{4}{{(x + 3)}^{2}}$ $-4/(x+3)^2$

How do you find the derivative of 4 / (x+3)4x+34 / (x+3)?