Question #13856

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Question #13856

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Answer 1 · 2016-05-23T23:54:17

The standard form for the equation of a circle is (x-h) ${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$ , with the center of the circle being at $(h, k)$ $(h,k)$ . Thus the center of the circle is $- 1 \cdot 36 = - 36$ $-1*36=-36$ and $- 1 \cdot (- 4) = 4$ $-1*(-4)=4$ , and the radius is $\sqrt{9} = 3$ $sqrt(9)=3$

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Question #13856

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