What is the standard form of $y = (x + 3) (x^{2} - 3 x + 9)$ $y=(x+3)(x^2 - 3x + 9)$ ?

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What is the standard form of $y = (x + 3) (x^{2} - 3 x + 9)$ $y=(x+3)(x^2 - 3x + 9)$ ?

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Answer 1 · 2016-05-23T00:07:18

$y = x^{3} + 27$ $y=x^3 + 27$

Explanation:

We have

$y = (x + 3) (x^{2} - 3 x + 9)$ $y=(x+3)(x^2 - 3x + 9)$ .

We need to expand this using the Distributive Property.

$y = (x + 3) (x^{2} - 3 x + 9)$ $y=(x+3)(x^2 - 3x + 9)$

$= x \cdot (x^{2} - 3 x + 9) + 3 \cdot (x^{2} - 3 x + 9)$ $=x*(x^2 - 3x + 9) + 3*(x^2 - 3x + 9)$ .

We multiply these through to get

$y = x^{3} - 3 x^{2} + 9 \cdot x + 3 \cdot x^{2} - 9 x + 27$ $y=x^3 - 3x^2 + 9*x + 3*x^2 - 9x + 27$ .

Collecting like terms we have

$y = x^{3} + 27$ $y=x^3 + 27$ .

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What is the standard form of $y = (x + 3) (x^{2} - 3 x + 9)$ $y=(x+3)(x^2 - 3x + 9)$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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What is the standard form of y=(x+3)(x2−3x+9)y=(x+3)(x^2 - 3x + 9) ?

1 Answer

Explanation:

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What is the standard form of $y = (x + 3) (x^{2} - 3 x + 9)$ $y=(x+3)(x^2 - 3x + 9)$ ?