Question #600a1

1 Answer
L.Shane John Paul N.
May 15, 2016

#400 Omega#. #R = R_1 + R_2# , as they are in series.

Explanation:

When resistances are connected in series, same current flows through them. Therefore, according to Ohm's law(#V=I*R#)

Let,
#V_1=#potential difference across #R_1#
#V_2=#potential difference across #R_2#

As they are in series,

#V_"total"=V_1+V_2#
So,
#I*R_"total"=I*R_1+I*R_2#

Therefore,
#R_"total"=R_1+R_2#

So, the answer here is #300+100=400 Omega#.

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