How do you graph $[sin x]$ $[sin x]$ ?

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Answer 1 · 2016-05-13T15:46:53

The $sin$ $sin$ function is a periodic function that ranges between -1 and 1.

Knowing that the $sin$ $sin$ function is a periodic function that ranges between -1 and 1. Some values of interest help us to draw the graph.

$sin (0) = 0$ $sin(0)= 0$

$sin (\frac{π}{4}) = \frac{\sqrt{2}}{2}$ $sin(pi/4)= sqrt(2)/2$

$sin (\frac{π}{2}) = 1$ $sin(pi/2)=1$

$sin (3 \frac{π}{4}) = \frac{\sqrt{2}}{2}$ $sin(3pi/4)=sqrt2/2$

$sin (π) = 0$ $sin(pi)=0$

$sin (5 \frac{π}{4}) = - \frac{\sqrt{2}}{2}$ $sin(5pi/4)=-sqrt(2)/2$

$sin (3 \frac{π}{2}) = - 1$ $sin(3pi/2)=-1$

$sin (2 π) = 0$ $sin(2pi)=0$

These points complete the first period.

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How do you graph [sinx] [sin x] ?