How do you solve ${sin}^{- 1} x = \frac{4}{2}$ $sin^ -1x= 4/2$ ?

Question

1677 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-07T10:52:55

x = $sin (\frac{4}{2})$ $sin (4/2)$

${sin}^{- 1} (x) = \frac{4}{2}$ $sin^-1(x) = 4/2$ can be express into
$sin (\frac{4}{2}) = x$ $sin (4/2) = x$

Note this question must be in degree º

How do you solve sin^ -1x= 4/2 sin−1x=42sin^ -1x= 4/2 ?