How do you solve $2 y = 4 x - 16$ $2y = 4x - 16$ and $5 y = 4 x + 8$ $5y = 4x + 8$ ?

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How do you solve $2 y = 4 x - 16$ $2y = 4x - 16$ and $5 y = 4 x + 8$ $5y = 4x + 8$ ?

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Answer 1 · 2016-05-03T06:42:36

Okay we will solve this step by step

Let $2 y = 4 x - 16$ $2y=4x-16$ be equation number 1
and $5 y = 4 x + 8$ $5y=4x+8$ be equation number 2

$4 x$ $4x$ is same in both equations that is to say has same coefficient $4 x$ $4x$

So we will subtract both of them
$+ 5 y = + 4 x + 8$ $+5y=+4x+8$
$- 2 y = - 4 x + 16$ $-2y=-4x +16$
This results in
$3 y = 24$ $3y=24$
$y = 8$ $y=8$ Substituting this value in equation number 2

$5 (8) = 4 x + 8$ $5(8)=4x+8$
$40 = 4 x + 8$ $40=4x+8$
$40 - 8 = 4 x$ $40-8=4x$
$32 = 4 x$ $32=4x$
$\frac{32}{4} = x$ $32/4=x$
$8 = x$ $8=x$

So we get $x = 8$ $x=8$ and $y = 8$ $y=8$

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How do you solve $2 y = 4 x - 16$ $2y = 4x - 16$ and $5 y = 4 x + 8$ $5y = 4x + 8$ ?

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