How do you solve $4+ n/3 < 6$ ?

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Answer 1 · 2016-04-25T16:36:45

$n<6$

$4+n/3<6$

Multiply the inequality by 3

$=>12+n<18$

Subtract 12 from both sides

$=>12+ncolor(red)(-12)<18color(red)(-12)$

$=>n<6$

How do you solve 4+ n/3 < 64+ n/3 < 6?