What is the standard form of #y= (x+7)(x-8)^2 #?

1 Answer
Edmund Liew
Apr 25, 2016

#y = (x+7)(x-8)(x-8)#
See below..

Explanation:

#(x-8)^2# means #(x-8)(x-8)#

#y = (x+7)(x-8)(x-8)#
#y = (x+7)(x^2-8x-8x+64)#
#y =(x+7)(x^2-16x+64) #

then break the (x+7) up,
#x(x^2-16x+64)+7(x^2-16x+64)#

#=x^3-16x^2+64x+7x^2-112x+448#

#=x^3-9x^2-48x+512# is your final answer

Note: PLEASE PLEASE PLEASE! Be very careful with positives and negatives!!

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