How do you factor completely #x^2 + 12xy + 35y^2#?

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Answer 1 · 2016-04-25T11:10:51

#x^2 + 12xy+35y^2#
#=x^2+2.x.6y+35y^2#
#=x^2+2.x.6y+(6y)^2-y^2#
#= (x+6y)^2-y^2#
#= (x+6y+y)*(x+6y-y)#
#=(x+7y)(x+5y)#