How do you factor completely # 2x^2 + 36x + 162#?

1 Answer
Edmund Liew
Apr 25, 2016

See below..

Explanation:

#2x^2 + 36x + 162# (divide 2) gives you:
#x^2 + 18x + 81#, then you have to factorise it.

When you factorise it, it should look like that: #(x + a)(x + b) = 0#

But before you factorise, you should first find out what factors (a and b) of 81 that add to 18. In that case, 9 and 9 are the factors that add to 18 and multiply to 81.

#(x+9)(x+9)#

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