How do you solve #4^(x +4) = 5^((2x)/ 5)#?

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Answer 1 · 2016-04-21T17:15:31

#x=(4ln4)/(ln4-2/5 ln5)~~7.47#

#ln 4^(x+4)=ln 5^(2/5 x)#

#(x+4)ln4=2/5 xln5#

#xln4+4ln4-2/5 x ln5=0#

#xln4-2/5 x ln5=4ln 4#

#x(ln4-2/5 ln5)=4ln4#

#x=(4ln4)/(ln4-2/5 ln5)~~7.47#