How many molecules are in 5.35 moles of $H_{2} O$ $H_2O$ ?

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How many molecules are in 5.35 moles of $H_{2} O$ $H_2O$ ?

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Answer 1 · 2016-04-20T05:55:45

$3.22 \times 10^{24}$ $3.22×10^24$ molecules $H_{2} O$ $H_2O$

Explanation:

Avogadro's number states that every mole has
$6.022 \cdot 10^{23}$ $6.022⋅10^23$ atoms (or molecules, depending on the substance).

So to figure this out you have to assume that $1 m o l H_{2} O = 6.022 \times 10^{23}$ $1 mol H_2O = 6.022×10^23$

So set up a conversion.

$5.35 m o l$ $5.35mol$ $H_{2} O$ $H_2O$ ( $6.022 \times 10^{23}$ $6.022×10^23$ molecules / 1 $m o l$ $mol$ )
$1 M o l$ $1 Mol$ cancels out with $m o l H_{2} O$ $mol H_2O$ .

$5.35 \times 6.022 \times 10^{23} = 3.22 \times 10^{24}$ $5.35×6.022×10^23=3.22×10^24$ molecules of $H_{2} O$ $H_2O$

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How many molecules are in 5.35 moles of $H_{2} O$ $H_2O$ ?

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