What is the slope-intercept form of #8x - 4y = 16 #?

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Answer 1 · 2016-04-16T22:31:48

2

Make sure that the standard form turns into slope-intercept form (which is #y = mx + b#).

Therefore, bring 8x to the other side of the equal sign by subtracting it from both sides.
#8x - 8x - 4y = 16 - 8x#
#-4y = 16 - 8x#

Isolate y by dividing all of the terms by -4.
#(-4y = 16 - 8x)/(-4)#

#y = -6 + 2x#

Remember that in #y = mx + b#, the m represents the slope.

In this case, 2 is the coefficient with x.

Therefore, the slope is 2.