What is the standard form of #y= (x-2) (5x+3) #?

1 Answer
H Dev
Apr 16, 2016

Remember that the standard form of quadratics is #ax^2 + bx + c = 0#

Explanation:

#y = (x - 2)(5x + 3)#
is in factored form.

You want to now expand it, so you can use FOIL (or First, Outer, Inner, Last)

In other words in this case you would really distribute the terms in the first parenthesis with the terms in the second parenthesis.

You would have something like:
#x(5x) + x(3) + (-2)(5x) + (-2)(3)#

Then you are just left to multiply each of the terms.
#5x^2 + 3x - 10x - 6#

Combine the like terms to now get
#5x^2 - 7x - 6#

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