Question #dc275

1 Answer
Rui D.
Apr 14, 2016

#0.028#

Explanation:

Considering only the darts that reach the range target, it's reasonable to suppose that the probability is proportional to the useful area.

So, with #p_T=1# corresponding to #pi*6^2# #["inches"^2]# (the total area of the range target), we have

#p/p_T="Area of 10 points"/(pi*6^2)#
#p/1=(cancelpi*1^2)/(cancelpi*6^2)#
#p=1/36=0.02777~=0.28#

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