How many moles of #(NH_4)_2SO_4# are present in 25.0 grams of #(NH_4)_2SO_4#?

1 Answer
Manish Bhardwaj
Apr 13, 2016

0.2 moles

Explanation:

Mass of one mole of Ammonium Sulfate is 132 g

We can set up conversion factors/ ratios

1 mol Ammonium Sulfate = 132g of # (N#H4#)_2#S#O_4#

1 mol Ammonium Sulfate / 132g of # (N#H4#)_2#S#O_4# (a)

and

132g of # (N#H4#)_2#S#O_4# / 1 mol of Ammonium Sulfate (b)

Using the conversion factor (a) we can find number of moles.

25 g # (N#H4#)_2#S#O_4# x 1 mol of Ammonium sulfate / 132g of # (N#H4#)_2#S#O_4#

0.2 moles Ammonium sulfate

Related questions
See all questions in The Mole
Impact of this question
2116 views around the world
You can reuse this answer
Creative Commons License