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What is the formula for lead (IV) oxide?

1 Answer

Manish Bhardwaj

Apr 11, 2016

Pb#O_2#

Explanation:

For each # Pb^(4+) # we need two negative oxide ions #O^(2-)# to balance out total positive and total negative charge.

The ratio of # Pb^(4+) # and #O^(2-)# ios is 1:2 and hence the formula is Pb#O_2#.

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