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How do you find #abs( -3+4i)#?

1 Answer

Mar 30, 2016

#|-3+4i|=sqrt((-3)^2+4^2)=5#

Explanation:

Let #z=x+iy# be any complex number in rectangular form.

Then its modulus is given by #|z|=sqrt(x^2+y^2)#.

So in this case we get

#|-3+4i|=sqrt((-3)^2+4^2)=sqrt25=5#

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