The force applied against a moving object travelling on a linear path is given by F(x)= sinx + 2. How much work would it take to move the object over x in [ 0,pi/3] ?

1 Answer
Mar 25, 2016

1/2+2*pi/3 Joules

Explanation:

The work necessary is dW=F(x)*dx

as the movement is between 0 and 3 metres

W=int_0^3 F(x) dx = int_0^3 (senx + 2) dx =1/2+2*pi/3 due to

cos(pi/3) = 1/2