How do you simplify $x^{- 4} \cdot x^{- 7} \cdot x^{5}$ $x^-4x^-7x^5$ ?

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Answer 1 · 2016-03-22T13:57:39

$x^{- 6}$ $x^-6$

When two similar numbers are multiplied, their powers can be added.

Therefore:
$x^{- 4} \cdot x^{- 7} \cdot x^{5} = x^{- 4 - 7 + 5}$ $x^-4*x^-7*x^5 = x^(-4-7+5)$
$= x^{- 6}$ $=x^-6$

which can then be further simplified to a term without negative exponents as $\frac{1}{x^{6}}$ $1/x^6$

How do you simplify x−4⋅x−7⋅x5 x^-4*x^-7*x^5?