How do you write the expression $(x + 6) (x - 2)$ $(x+6)(x-2)$ as a polynomial in standard form?

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How do you write the expression $(x + 6) (x - 2)$ $(x+6)(x-2)$ as a polynomial in standard form?

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Answer 1 · 2016-03-21T15:57:30

The final answer: $x^{2} + 4 x - 12$ $x^2 + 4x - 12$

Explanation:

To write the expression $(x + 6) (x - 2)$ $(x + 6) (x - 2)$ in standard form you can FOIL (First Outer Inner Last).

$x \times x = x^{2}$ $x xx x = x^2$

$x \times (- 2) = - 2 x$ $x xx (-2) = -2x$

$6 \times x = 6 x$ $6 xx x = 6x$

$6 \times (- 2) = - 12$ $6 xx (-2) = -12$

After foiling completely you get:

$x^{2} - 2 x + 6 x - 12$ $x^2 - 2x + 6x -12$

Next, you combine like terms.

$- 2 x + 6 x = 4 x$ $-2x + 6x = 4x$

There are no other like terms. Therefore, your final answer is

$x^{2} + 4 x - 12$ $x^2 + 4x - 12$

Answer 2 · 2016-03-21T23:12:48

It's really a lot easier to see the FOIL method than explain.

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Then, once foiled out, combine like terms.
Your final answer will be, x^2 +4x -12

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How do you write the expression $(x + 6) (x - 2)$ $(x+6)(x-2)$ as a polynomial in standard form?

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Explanation:

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