How do you find all the zeros of $g(x) = 2x^3 + x^2 - 6x - 3$ ?

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Answer 1 · 2016-03-13T03:48:26

$x=sqrt(3)$ and $x=-1/2$

First of all, let us factorize your equation $2x^3+x^2−6x−3$ . We can display the equation in the following format:

$x^2(2x+1)-3(2x+1)$ ========> $(x^2-3)(2x+1)$

Now we can find the zeros:

$x=sqrt(3)$ and $x=-1/2$

If there are any further questions, let me know

How do you find all the zeros of g(x) = 2x^3 + x^2 - 6x - 3g(x) = 2x^3 + x^2 - 6x - 3?