How do you find the definite integral of #int (1-2x-3x^2)dx# from #[0,2]#?

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How do you find the definite integral of #int (1-2x-3x^2)dx# from #[0,2]#?

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Answer 1 · 2016-03-11T22:26:25

#int_0^2(1-2x-3x^2)d x=-10#

Explanation:

#int_0^2(1-2x-3x^2)d x=|x-2*1/2*x^2-3*1/3*x^3|_0^2#
#int_0^2(1-2x-3x^2)d x=|x-x^2-x^3|_0^2#
#int_0^2(1-2x-3x^2)d x=2-2^2-2^3#
#int_0^2(1-2x-3x^2)d x=2-4-8#
#int_0^2(1-2x-3x^2)d x#
#int_0^2(1-2x-3x^2)d x=-10#

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How do you find the definite integral of #int (1-2x-3x^2)dx# from #[0,2]#?

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