How do you find the determinant of #((2, 1), (-1, 3))#?
1 Answer
Mar 10, 2016
7
Explanation:
For the general 2X2 matrix :
#((a,b),(c,d))# The determinant is : ad - bc written
#| (a,b),(c,d)| = ad - bc# For the matrix here: a = 2 , b = 1 , c =-1 and d = 3
hence determinant
#= (2xx3) - (1xx-1) = 6 + 1 = 7#
