An object with a mass of #6 kg# is moving at #7 m/s# over a surface with a kinetic friction coefficient of #2 #. How much power will it take to accelerate the object at #8 m/s^2?

1 Answer
Sidharth
Mar 4, 2016

#P = W/ t = F *s/t = Fv = 168 * 7 = 1176W#

Explanation:

#P = W/ t = F *s/t = Fv#

#f = mu mg = 2 * 6 * g#
# a_f = mu g = 2* 10 =20#

#F_(Net) = m_(Net) a_(Net)#

#a _( Net) = a_f + a = 8 + 20 = 28 m/s^2 #

#F_(Net) = m_(Net) a_(Net) = 6 * 28 = 168 N#

#P = W/ t = F *s/t = Fv = 168 * 7 = 1176W#

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