What is the standard form of #y= (x - 8) (4x+1) #?

1 Answer
A. S. Adikesavan
Mar 3, 2016

The quadratic form is y = #4x^2-31x-8#.
If it is for making a graph, the standard form is
#(x-31/8)^2 = 4(1/16)(y+993/16)#.

Explanation:

The equation represents the parabola with .
Vertex: #(31/8, -993/16)#,
Axis: Parallel to +ve y-axis,
Focus at #(31/8, -993/16 +1/16)# and
Directrix along x = #(31/8, -993/16 -1/16) #.

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