How do you evaluate $sin (\frac{23 π}{6})$ $sin((23pi)/6)$ ?

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Answer 1 · 2016-03-03T08:15:38

$sin (\frac{23 π}{6}) = - \frac{1}{2}$ $sin ((23pi)/6) = -1/2$

$sin (\frac{23 π}{6})$ $sin ((23pi)/6)$

$= sin (690) = sin (2 \cdot 360 - 30) = sin (- 30) = - sin 30$ $= sin (690) = sin (2*360 - 30)= sin (-30) = - sin30$

$sin 30 = \frac{1}{2}$ $sin 30 = 1/2$

$\Rightarrow sin 690 = - \frac{1}{2}$ $=>sin 690 = -1/2$

How do you evaluate sin((23pi)/6) sin(23π6)sin((23pi)/6) ?