What is the domain and range of $g (x) = (1 - x^{2})$ $g(x)=(1-x^2)$ ?

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What is the domain and range of $g (x) = (1 - x^{2})$ $g(x)=(1-x^2)$ ?

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Answer 1 · 2016-03-01T13:02:10

domain would be (-infinity to infinity)

Answer 2 · 2016-03-01T13:10:22

The domain would be unlimited, as there are no 'forbidden' values for $x$ $x$ (no fractions, no roots).
Domain $= (- \infty, + \infty)$ $=(-oo,+oo)$

Explanation:

For the range we observe that the maximum value of $g (x)$ $g(x)$ happens when $x = 0$ $x=0$ (which means the least to subtract from 1).
Any other value of $x$ $x$ would make $x^{2} > 0 \to g (x) < 1$ $x^2>0->g(x)<1$
Range $= (- \infty, 1]$ $=(-oo,1]$

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What is the domain and range of $g (x) = (1 - x^{2})$ $g(x)=(1-x^2)$ ?

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