What is the vertex, axis of symmetry, of y=5x^2 - 8x -6y=5x2−8x−6? Does the parabola open up or down?

1 Answer
Janae
Feb 29, 2016

AOS: x= 0.8
Vertex: (0.8, -9.2)
Parabola opens: up.

Explanation:

Axis of Symmetry (vertical line that divides the parabola into two congruent halves): x= 0.8
Found by using formula: -b/(2a)−b2a.
(ax^2+bx+cax2+bx+c, in this case b = -8−8)

Vertex (peak in the curve): (0.8, -9.2)
Can be found by imputing the Axis of Symmetry for x to find the y.
y= 5(0.8)^2-8(0.8)-65(0.8)2−8(0.8)−6 y= -9.2

The parabola opens up since the a value of this graph is positive.
(ax^2+bx+cax2+bx+c, in this case a = 55)

You can also find all of this information by looking at it on the graph:
graph{y=5x^2-8x-6 [-8.545, 11.455, -13.24, -3.24]}

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