If a projectile is shot at a velocity of $7 \frac{m}{s}$ $7 m/s$ and an angle of $\frac{π}{4}$ $pi/4$ , how far will the projectile travel before landing?

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Answer 1 · 2016-02-20T18:47:26

1.25m

The range of a projectile is calculated as

$x = \frac{v^{2} . {sin}^{2} α}{2 . g}$ $x=(v^2.sin^2 alpha)/(2.g)$

$h e r e, V = 7, α = 45$ $here, V=7,alpha=45$ $g = 9.8 \frac{m}{s^{2}}$ $g=9.8m/s^2$

= $\frac{7^{2} . {(1 / \sqrt{2})}^{2}}{2 . 9.8}$ $(7^2.(1//sqrt2)^2)/(2. 9.8)$

= $\frac{(\frac{49}{2})}{19.6}$ $((49/2))/19.6$

=1.25m

If a projectile is shot at a velocity of 7ms7 m/s and an angle of π4pi/4, how far will the projectile travel before landing?