How do you expand $log (3 \cdot 2^{3})$ $log(3*2^3)$ ?

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Answer 1 · 2016-02-20T18:08:05

$1.5154$ $1.5154$

Applying the log rule log ${log}_{a} (x^{b})$ $log_a(x^b)$ = b. ${log}_{a} (x)$ $log_a(x)$

= $3 . {log}_{10} (3.2)$ $3.log_10(3.2)$

= $3 . 0.50551$ $3. 0.50551$

= $1.5154$ $1.5154$

How do you expand log(3*2^3)log(3⋅23)log(3*2^3)?