What volume does #7.54 * 10^25# atoms #Ne# occupy at STP?

1 Answer
Ayako_Sho
Feb 20, 2016

Simple,
First conver #7.54 xx 10^25# atoms of Ne to moles

To do this, use the equation
Number of particles = Number of moles x Avogadro's constant

Since what we have to find out here is number of moles, rearrange the equation and solve for number of moles

Number of moles = Number of particles/Avogadro's Constant
#=7.54 xx 10^25//6.02 xx 10^23#
#= 125.24#
Thus, there are 125.24 moles in #7.54 xx 10^25# atoms of Ne

Now, the volume of anything at STP is equal to the number of moles multiplied by 22.4 L

Volume(at STP) = No. of moles x 22.4
#= 125.24 xx 22.4#
#= 2805 L//mol#
Thus, the volume is 2805 L/mol at STP for neon

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