If a 2 kg object is constantly accelerated from 0m/s to 16 m/s over 6 s, how much power musy be applied at t=1 ?

1 Answer
Joaquín M.
Feb 14, 2016

16/3Newtons

Explanation:

The second Newton's law says

F=m*a where m is the mass, F the power and a the acceleration.
As the acceleration is constant => a=(v_f -v_0)/t = 16 m/s / 6s = 8/3 m/s^2
Then, the power applied is F=2kg*8/3 m/s^2 = 16/3 N.

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