How much power is required to lift an object of weight #595# newtons by #3.15# meters in #15.2# seconds?

1 Answer
Shwetank Mauria
Feb 10, 2016

Power output is #123.306# watts.

Explanation:

Potential Energy (in Joules) #PE# gained is given by

#PE# = #m*g*h#, where #m# is mass in kilograms, #g# is acceleration due to gravity (#9.8# meters per #second^2#) and #h# is height in meters. We can also write this as #PE# = #w*h#, where #w# is weight in Newtons - as it is given in Newtons here. (Obviously #w=m*g#).

Power in watts is given by #(PE)/t#, where #t# is times in seconds.

Accordingly #PE# here is #595*3.15# or #1,874.25# and

Power output is #1874.25/15.2# or #123.306# watts.

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