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Question #7d77c

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Feb 9, 2016

If $A (x_{1}, y_{1})$ $A(x_1,y_1)$ and $B (x_{2}, y_{2})$ $B(x_2,y_2)$ are two points then the mid-point between $A$ $A$ and $B$ $B$ is given by:

$C = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$ $C=((x_1+x_2)/2,(y_1+y_2)/2)$

Where $C$ $C$ is the mid-point.

Here, let $A = (5, 7)$ $A=(5,7)$ and $B = (- 2, - 8)$ $B=(-2,-8)$

$\Rightarrow C = (\frac{5 - 2}{2}, \frac{7 - 8}{2}) = (\frac{3}{2}, - \frac{1}{2})$ $implies C=((5-2)/2,(7-8)/2)=(3/2,-1/2)$

Hence, the mid-point between the given points is $(\frac{3}{2}, - \frac{1}{2})$ $(3/2,-1/2)$ .

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