How do you find the determinant of #((-9, -7), (4, 5))#?

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Answer 1 · 2016-02-09T11:05:16

The determinant is #-17#.

For a #2 times 2# matrix

#A = ( (a, b), (c, d)) #,

the determinant can be computed as

#|A| = a * d - b * c#

Thus, in your example,

#abs( ( (-9, -7), (4, 5) ) ) = -9 * 5 - (-7)* 4 = -45 + 28 = -17#