A block of silver has a length of 0.93 m, a width of 60 mm and a height of 12 cm. How do you find the total resistance of the block if it is placed in a circuit such that the current runs along its length? Along its height? Along its width?

1 Answer
ali ergin
Feb 4, 2016

for alongside length:
#R_l=0,73935*10^(-8) Omega#
for alongside width:
#R_w=0,012243*10^(-8) Omega#
for alongside height:
#R_h=2,9574*10^(-8) Omega#

Explanation:

#"formula required:"#
# R= rho *l/s#
# rho=1,59*10^-8#
#R= rho *(0,93)/(0,12*0,06)= rho*0,465#
#"for alongside length"#
#R=1,59*10^-8*0,465=0,73935*10^(-8) Omega#

#R= rho *(0,06)/(0,93*0,12)= rho*0,0077#
#"for alongside width"#
#R= 1,59*10^(-8)*0,0077=0,012243*10^(-8) Omega#

#R= rho *(0,12)/(0,06*0,93)= rho*1,86#
#" for alongside height"#
#R=1,59*10^(-8)*1,86=2,9574*10^(-8) Omega#

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