How do you find the inverse of #y = -log_4x#?

1 Answer
Rohan A.K
Feb 2, 2016

#f^-1(x)=4^-x#

Explanation:

Given that #y=-log_4x#. It can also be written as #f(x)=-log_4x#
This means that #f(x)=y\impliesf^-1(y)=x#

Now, I believe you're accustomed to the realm of logarithms so that you know #y=-log_4x\implies-y=log_4x\implies4^-y=x#
We've written above that #f^-1(y)=x# so that just means #f^-1(y)=4^-y#.
Replacing the #y# parameter by the #x# parameter is just what you'll find to be the answer.

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