What is #log 100 + log 10#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Sihan Tawsik Feb 1, 2016 3 Explanation: #log100+log10# #=log10^2+1#[as #log10=1#] #=2log10+1# #=2+1# #=3# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 7425 views around the world You can reuse this answer Creative Commons License