What is (-3x^2-11x + 13)-(18x^2 +19x-8)(−3x2−11x+13)−(18x2+19x−8)?

2 Answers
Daksh S.
Feb 1, 2016

-21x^2-30x+21−21x2−30x+21

Explanation:

This can be written as -3x^2-11x+13 +[ (-1)xx(18x^2+19x-8)]−3x2−11x+13+[(−1)×(18x2+19x−8)]
-3x^2-11x+13+(-18x^2-19x+8)−3x2−11x+13+(−18x2−19x+8)
(-3-18)x^2+(-11-19)x+(13+8)(−3−18)x2+(−11−19)x+(13+8)
-21x^2-30x+21−21x2−30x+21

Veddesh phiϕ
Feb 1, 2016

(-3x^2-11x+13)-(18x^2+19x-8)(−3x2−11x+13)−(18x2+19x−8)

Always remember that you must multiply your signs and write when subtracting:

rarr=(-3x^2-11x+13)-18x^2-19x+8→=(−3x2−11x+13)−18x2−19x+8

Remove brackets:

rarr-3x^2-11x+13-18x^2-19x+8→−3x2−11x+13−18x2−19x+8

rarr-21x^2-11x+13-19x+8→−21x2−11x+13−19x+8

rarr-21x^2-30x+13+8→−21x2−30x+13+8

rarr=-21x^2-30x+21→=−21x2−30x+21 (Final answer)

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