If #f(x) = sqrt(25-x^2)#, what is the value of #f(3)#?

1 Answer
Neil
Jan 29, 2016

4 :)

Explanation:

since #f(3) = sqrt(25 - x^2)#,

we subtitute the value of x for 3 since f(3)
#f(3) = sqrt(25 - 3^2)#

then evaluate the terms inside the radical sign (square root)
#f(3) = sqrt(25 - 9)#
#f(3) = sqrt(16)#

then finalize the answer, since #4*4 = 16#, the square root of #16# is 4, hence the answer is:
#f(3) = 4#

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